def is_palindrome(n): lt1 = str(n)[-1::-1] lt2 = str(n)[::1] b=True for i in range(len(lt1)): if lt1[i] !=lt2[i]: b = False break return b print(list(filter(is_palindrome,range(1,1000))))
Sign in to make a reply
湖南大学微软技术俱乐部