交作业
Topic source
支持复数解输出
def quadratic(a, b, c):
import math
delt=b*2 - 4ac
if delt >= 0:
r1 = (-b + math.sqrt(delt))/(2a)
r2 = (-b - math.sqrt(delt))/(2a)
else:
delt = -delt
r1 = complex(-b/(2a) , math.sqrt(delt)/(2a))
r2 = complex(-b/(2a) , -math.sqrt(delt)/(2*a))
return r1, r2
- 1
疯羊在田
-- coding: utf-8 --
import math
def quadratic(a, b, c): if not isinstance(a, (int, float)): raise TypeError('bad operand type') if not isinstance(b, (int, float)): raise TypeError('bad operand type') if not isinstance(c, (int, float)): raise TypeError('bad operand type') pan = b*2 - 4ac if pan<0: return '此方程无解' elif pan==0: x = -b/(2a) return x elif pan>0: x1 = (-b + math.sqrt(pan))/(2a);x2 = (-b - math.sqrt(pan))/(2a) return x1, x2
print(quadratic(4, 3, 1)) print(quadratic(1, 3, -4))