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遗弃之城

#1 Created at ... [Delete] [Delete and Lock User]

方案一：

L1 = ['Hello', 'World', 18, 'Apple', None]
L2 = [s.lower()for s in L1 if isinstance(s,str)]
print (L2)

方案二：

L1 = ['Hello', 'World', 18, 'Apple', None]
L2 = []
for i in L1:
    if isinstance(i,str):
        L2.append(i)
    else:
        pass
L3 = [s.lower() for s in L2]
print (L3)

叫我王奋斗

#2 Created at ... [Delete] [Delete and Lock User]

我就用的第二个，好复杂，觉得大家好聪明啊都能想到第一个那么简洁的。。。看到差距拉~~~

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