1题
def normalize(name): return name[0].upper()+name[1:].lower()
2题
def prod(L): return reduce(lambda x,y:x*y,L)
3题
def str2float(s): def char2num(C): return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}[C] a,b=s.split('.') #整数部分=(x*10+y);小数部分=(x*10+y)*0.1^(小数的位数) return reduce(lambda x, y: x*10+y, map(char2num, a)) + reduce(lambda x, y: x*10+y, map(char2num, b))*(0.1**len(b))
Sign in to make a reply
严肃的F同学
1题
2题
3题