import math
def quadratic(a, b, c):
dt = b**2 - 4*a*c if a == 0: x = (-c)/b return x elif dt < 0: return '方程无实数根' else: x1 = (-b + math.sqrt(dt))/(2*a) x2 = (-b - math.sqrt(dt))/(2*a) return x1, x2 pass
print(quadratic(2, 3, 1))
print(quadratic(1, 3, -4))
Sign in to make a reply
用户4078073866
-- coding: utf-8 --
import math
def quadratic(a, b, c):
print(quadratic(2, 3, 1))
print(quadratic(1, 3, -4))