import math
def quadratic(a, b, c): m = bb-4ac if a==0: x=-c/b return '方程有唯一解%.2f' % x elif m<0: return '方程无解' elif m == 0: x=-b/(2a) return '方程有两个相同解%.2f' % x else: n=math.sqrt(m) x1=(-b+n)/(2a) x2=(-b+n)/(2a) return '方程有两个解：%.2f,%.2f' % (x1,x2)
Sign in to make a reply
Myron_W
-- coding: utf-8 --
import math
def quadratic(a, b, c): m = bb-4ac if a==0: x=-c/b return '方程有唯一解%.2f' % x elif m<0: return '方程无解' elif m == 0: x=-b/(2a) return '方程有两个相同解%.2f' % x else:
n=math.sqrt(m) x1=(-b+n)/(2a) x2=(-b+n)/(2a) return '方程有两个解：%.2f,%.2f' % (x1,x2)