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丁杰可爱时代

#1 Created at ... [Delete] [Delete and Lock User] 
    return base64.b64decode( s + b'='*( len(s) % 4 ) )

这样好像就好了

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#2 Created at ... [Delete] [Delete and Lock User]

帮后面的人解释一下这里 字符串运算符 * 重复输出字符串 返回临时变量(s + 待补全的b'=')

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