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逝去的9211

#1 Created at ... [Delete] [Delete and Lock User] 
    l=str(n)
    num=len(l)//2
    for x in range(0,num):
        if l[x]!=l[-1-x]:
            return False
    return True

逝去的9211

#2 Created at ... [Delete] [Delete and Lock User]

更简单的写法

return str(n)==str(n)[::-1]
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