import math def quadratic(a,b,c): n= bb-4ac if n<0: print('方程无解!') else : x1= (-b+math.sqrt(n))/(2a) x2= (-b-math.sqrt(n))/(2*a) return x1,x2
Sign in to make a reply
生吃胡萝北
quadratic.py
import math def quadratic(a,b,c): n= bb-4ac if n<0: print('方程无解!') else : x1= (-b+math.sqrt(n))/(2a) x2= (-b-math.sqrt(n))/(2*a) return x1,x2