想请教下，为什么用 r'' 不能输出奇数个 \ 呢？

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#1 Created at ... [Delete] [Delete and Lock User]

print(r'\\') File "<stdin>", line 1 print(r'\\') ^ SyntaxError: EOL while scanning string literal

#2 Created at ... [Delete] [Delete and Lock User]

>>> print(r'\\')
\\

#3 Created at ... [Delete] [Delete and Lock User]

我的print(r'\') 输出就是：\ 没有问题啊。

#4 Created at ... [Delete] [Delete and Lock User]

我看到题主的问题，自己试了下，直接1个print的话，确实无法输出奇数个\；我用的shell；

#5 Created at ... [Delete] [Delete and Lock User]

可惜无法配图 @廖雪峰

#6 Created at ... [Delete] [Delete and Lock User]

#7 Created at ... [Delete] [Delete and Lock User]

print(r'\')的确是会报错的。我的理解是： r''只是将单引号里存在的转义操作取消，而这个例子里单引号区域内只有转义符\，故r''无法发挥作用，解释器就理解为r'\'这个字符串少了单引号或者双引号来包括，故报错。

#8 Created at ... [Delete] [Delete and Lock User]

支持，很有说服力的理解！

#9 Created at ... [Delete] [Delete and Lock User]

修改一下： 解释器就理解为r'\'是一个字符串，语法上少了单引号或者双引号来包括，故报错。

#10 Created at ... [Delete] [Delete and Lock User]

再次修改.. 刚再试了一遍，看了看报错，觉得解释器是将r'\'理解为: 先执行\'将'转义出来了，所以接下来语法r''便少了第二个单引号。报错。 以上皆个人猜测 -_-