n = (b*b - 4*a*c) if n > 0: x1 = (-b + math.sqrt(n)) / (2*a) x2 = (-b - math.sqrt(n)) / (2*a) return x1, x2 elif n == 0: x1 == x2 == -b/(2*a) return x1 else: print('无解')
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