import java.util.*;
public class Main {
public static void main(String[] args) {
// 构造从start到end的序列:
final int start = 10;
final int end = 20;
List<Integer> list = new ArrayList<>();
for (int i = start; i <= end; i++) {
list.add(i);
}
// 随机删除List中的一个元素:
int removed = list.remove((int) (Math.random() * list.size()));
int found = findMissingNumber(start, end, list);
System.out.println(list.toString());
System.out.println("missing number: " + found);
System.out.println(removed == found ? "测试成功" : "测试失败");
}
static int findMissingNumber(int start, int end, List<Integer> list) {
int found = 0;
for (int i = 0; i < list.size(); i ++) {
if (list.get(i) == start) {
start ++;
continue;
}
found = start;
}
return found;
}
}
练习二: 增强版:和上述题目一样,但整数不再有序,试找出缺失的数字:
import java.util.*;
public class Main {
public static void main(String[] args) {
// 构造从start到end的序列:
final int start = 10;
final int end = 20;
List<Integer> list = new ArrayList<>();
for (int i = start; i <= end; i++) {
list.add(i);
}
// 洗牌算法shuffle可以随机交换List中的元素位置:
Collections.shuffle(list);
// 随机删除List中的一个元素:
int removed = list.remove((int) (Math.random() * list.size()));
int found = findMissingNumber(start, end, list);
System.out.println(list.toString());
System.out.println("missing number: " + found);
System.out.println(removed == found ? "测试成功" : "测试失败");
}
static int findMissingNumber(int start, int end, List<Integer> list) {
Integer[] str = list.toArray(new Integer[list.size()]);
Arrays.sort(str);
int found = 0;
for (int i = 0; i < str.length; i ++) {
if (str[i] == start) {
start ++;
continue;
}
found = start;
}
return found;
}
}
唯情恋昉
练习作答
练习一: 给定一组连续的整数,例如:10,11,12,……,20,但其中缺失一个数字,试找出缺失的数字:
练习二: 增强版:和上述题目一样,但整数不再有序,试找出缺失的数字: