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不用循环不会做了

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苯叽

#1 Created at ... [Delete] [Delete and Lock User]

        int sum = 0;

        while (n > 0){

            sum = sum + n;

            n -= 1;

        }

秦臻秦臻

#2 Created at ... [Delete] [Delete and Lock User]

......我是直接把上面的公式写上了  sum = (1 + n) * n / 2;

杨森-ys

#3 Created at ... [Delete] [Delete and Lock User]

我也觉得是sum = (1 + n) * n / 2;   哈哈哈,应该还用不到while


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