Discuss / JavaScript / 懒惰的代码

懒惰的代码

Topic source

醉后诀

#1 Created at ... [Delete] [Delete and Lock User]

var name= document.getElementById('username').value; var psd= document.getElementById('password').value; var psd2= document.getElementById('password-2').value; var error = document.getElementById('test-error'); var Name=/[a-zA-Z0-9]{3,10}/ if (Name.test(name)) if(psd.length>=6&&psd.length<=20) if(psd===psd2) return true else error.innerText='两次输入口令必须一致' else error.innerText='口令必须是6-20位' else error.innerText='用户名必须是3-10位英文字母或数字' return false }


  • 1

Reply