es6这样写应该是最简单的吧

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#1 Created at ... [Delete] [Delete and Lock User]

arr.sort(); alert(欢迎${arr.slice(0,-1)}和${arr.pop()}同学！);

#2 Created at ... [Delete] [Delete and Lock User]

为什么``这个符号贴不出来呢

#3 Created at ... [Delete] [Delete and Lock User]

缺少一个Join，题目应该是中文的"，"分隔符，完善之后就是

arr.sort();
alert(`欢迎${arr.slice(0, 3).join('，')}和${arr.pop()}同学！`);

#4 Created at ... [Delete] [Delete and Lock User]

自己敲一遍一样的内容，结果总是错误，请问是哪个符号错了吗？alert(欢迎${arr.slice(0, 3).join('，')}和${arr.pop()}同学！); alert('欢迎${arr.slice(0,3).join('，')}和${arr.pop()}同学！');

#5 Created at ... [Delete] [Delete and Lock User]

`要转义吧\`

#6 Created at ... [Delete] [Delete and Lock User]

alert('欢迎${arr.slice(0,3).join('，')}和${arr.pop()}同学！'); 括号最外层不是单引号，是重音符 alert(欢迎${arr.slice(0,3).join('，')}和${arr.pop()}同学！);

#7 Created at ... [Delete] [Delete and Lock User]

concat()只会拆开第一层的数组 var a = [1, 2, 3]; a.concat(4, [5, [6, 7]]); // [1, 2, 3, 4, 5, [6, 7]]

#8 Created at ... [Delete] [Delete and Lock User]

alert(`欢迎${arr.sort().slice(0,-1)}和${arr.sort().pop()}同学!`) 在代码前后加两对反引号，就出来了，应该是编辑器的语法问题吧。那个djstjg slice和splice是不一样的