# -*- coding: utf-8 -*- import math def quadratic(a,b,c): if (b**2-4*a*c) < 0: return '该方程无解' elif a == 0: return 'a不能为0' else: x1 = (-b + math.sqrt(b*b-4*a*c))/(2*a) x2 = (-b - math.sqrt(b*b-4*a*c))/(2*a) return x1,x2 # print('quadratic(2,3,1)=',quadratic(2,3,1)) # print('quadratic(1,3,-4)=',quadratic(1,3,-4))
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