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filter 过滤函数

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def is_palindrome(n):

    n1=str(n)

    n2=n1[::-1]

    return n1==n2

output = filter(is_palindrome, range(1, 1000))

print('1~1000:', list(output))

if list(filter(is_palindrome, range(1, 200))) == [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191]:

    print('测试成功!')

else:

    print('测试失败!')


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