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def is_palindrome(n):

    n=str(n)

    if len(n)==1:

        return True

    elif len(n)%2==0 or (len(n)%2==1 and len(n)!=1):

        for i in range(len(n)//2):

            if n[i]==n[-(i+1)]:

                return True

    else:

        return False

output = filter(is_palindrome, range(1, 1000))

print('1~1000:', list(output))

if list(filter(is_palindrome, range(1, 200))) == [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191]:

    print('测试成功!')

else:

    print('测试失败!')

老哥,你这个我对1000,10000这种数好像会判断错误,认定成回数


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