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打卡

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天沢

#1 Created at ... [Delete] [Delete and Lock User]

    if len(s)!=0:

        while s[:1]==" ":

            s=s[1:]

        while s[-1:]==" ":

            s=s[:-1] 

    return s

翩若驚鴻

#2 Created at ... [Delete] [Delete and Lock User]

正解!

Sirius

#3 Created at ... [Delete] [Delete and Lock User]

要是不只一个空格就不对了


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