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Topic source
return reduce(fn,map(char2num,s1))+reduce(fn,map(char2num,s2))/1000
最好改为
reduce(fn,map(char2num,s1))+reduce(fn,map(char2num,s2))/10**len(list(map(char2num,s2)))
这样小数点四位及以上都可以这样做
- 1
return reduce(fn,map(char2num,s1))+reduce(fn,map(char2num,s2))/1000
最好改为
reduce(fn,map(char2num,s1))+reduce(fn,map(char2num,s2))/10**len(list(map(char2num,s2)))
这样小数点四位及以上都可以这样做
ZugumZug
作业3：
DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}
s1=s.split('.')[0]
s2=s.split('.')[1]
def fn(x,y):
return x*10+y
def char2num(s):
return DIGITS[s]
return reduce(fn,map(char2num,s1))+reduce(fn,map(char2num,s2))/1000