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def normalize(name):

    return name.capitalize()

def prod(L):

    def f(a,b):

        return a*b

    return reduce(f,L)

    DIGITS = {'.': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}

    def fn(x, y):

        return x * 10 + y

    def char2num(x):

        return DIGITS[x]

    return reduce(fn, map(char2num, s[:s.find('.')]))+reduce(fn, map(char2num, s[s.find('.'):]))/(10**(len(s)-s.find('.')-1))

shoppingxi

#2 Created at ... [Delete] [Delete and Lock User]

第三个解法不太好,一是DIGITS少了'0':0,二是只适用于含小数点的数,给个整数就错了


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