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记录一下

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XHS_12302

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# -*- coding: utf-8 -*-
# 力扣官解

def is_palindrome(n):
    if n < 0 or n % 10 == 0:
        return False
    revert_number = 0
    while n > revert_number:
        revert_number = revert_number * 10 + n % 10
        n = int(n / 10)
    return n == revert_number or n == int(revert_number / 10)

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