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    if len(L)>0:

        mi = min(L)

        ma = max(L)

        return (mi,ma)

    else:     

        return (None, None)

哎呀博雅

#2 Created at ... [Delete] [Delete and Lock User]

您这个也不是迭代方式啊

凡响skyline

#3 Created at ... [Delete] [Delete and Lock User]

以为自己很聪明?你用库函数min()、max()那还要你写个屁呀


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