#求n²+1(n从0开始)的和
n = int(input('输入n的值:'))
def sum(n):
y = 0
while n >= 0:
y = y + n**2+1
n = n - 1
return y
print('n²+1的和为:%d'%sum(n))
Sign in to make a reply
金甲神将9528
#求n²+1(n从0开始)的和
n = int(input('输入n的值:'))
def sum(n):
y = 0
while n >= 0:
y = y + n**2+1
n = n - 1
return y
print('n²+1的和为:%d'%sum(n))