Discuss / Python / 交作业

交作业

Topic source

sunbably

#1 Created at ... [Delete] [Delete and Lock User]

    x1=(-b+math.sqrt(b**2-4*a*c))/(2*a)

    x2=(-b-math.sqrt(b**2-4*a*c))/(2*a)

    return x1,x2


  • 1

Reply