Discuss / Python / 打开

打开

Topic source
import mathdef quadratic(a,b,c):    m = b*b - 4*a*c    if m >= 0:        print('answer')        x=(-b+math.sqrt(m))/(2*a)        y=(-b+math.sqrt(m))/(2*a)        return x,y    else:        return 'no answer'print(quadratic(2,3,1))

  • 1

Reply