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自定义函数练习

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榭柯靳

#1 Created at ... [Delete] [Delete and Lock User]

    delta = b ** 2 - 4 * a * c

    if delta < 0:

        print('方程无实数解')

    n = math.sqrt(delta)

    x1 = (-b+n)/(2 * a)

    x2 = (-b-n)/(2 * a)

    return x1 , x2

榭柯靳

#2 Created at ... [Delete] [Delete and Lock User]

import math

def quadratic(a, b, c):

 delta = b**2 - 4*a*c

 if delta < 0:

  print('方程无实数解')

 else:

  n = math.sqrt(delta)

  x1 = (-b+n)/(2*a)

  x2 = (-b-n)/(2*a)


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