Discuss / Python / 便捷答案
Back

便捷答案

Topic source

留白A_Z

#1 Created at ... [Delete] [Delete and Lock User]

- 代码

``` 

for i in [n1,n2]:

  print('{0}的16进制数为{1}'.format(i,hex(i)))

```

- 结果

> 255的16进制数为0xff 

   1000的16进制数为0x3e8

留白A_Z

#2 Created at ... [Delete] [Delete and Lock User]

居然不支持markdown

for i in [n1,n2]:
  print('{0}的16进制数为{1}'.format(i,hex(i)))
  • 1

Reply