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作业

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s凡s

#1 Created at ... [Delete] [Delete and Lock User] 
def pi(N):
    p, c = 0, 1
    for si in itertools.takewhile(lambda x: x <= 2 * N - 1, itertools.count(1,2)):
        p, c = p + c * 4 / si, -c
    return p

用户6398802611

#2 Created at ... [Delete] [Delete and Lock User]

看了一堆评论，就大佬的最牛逼，这种代码看起来就是舒服

Chris_Gardner_II

#3 Created at ... [Delete] [Delete and Lock User]

厉害啊, 敲简洁

不爱搞学术的动漫爱好者

#4 Created at ... [Delete] [Delete and Lock User]

牛逼！最简洁答案！

久违的双子座

#5 Created at ... [Delete] [Delete and Lock User]

尤其是自己在努力半天写一大堆后，再看到你的答案，真是厉害

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