def trim(s):
for i in s:
if i == ' ':
s = s[1:]
else:
break
for i in s[::-1]:
s = s[:-1]
return s
你这个才是正解
nice啊
切的操作太多了，每一次切一个字符都要切片一次，遇到特定情况（比如串很长并且首位空字符很多）效率会很低吧。
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微尘初心
def trim(s):
for i in s:
if i == ' ':
s = s[1:]
else:
break
for i in s[::-1]:
if i == ' ':
s = s[:-1]
else:
break
return s