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#1 Created at ... [Delete] [Delete and Lock User]

1.

def by_name(t): return t[0].lower()

2.

def by_score(t): return t[1]*(-1)

#2 Created at ... [Delete] [Delete and Lock User]

理解不了返回的t[0]为什么不是第一个tuple

#3 Created at ... [Delete] [Delete and Lock User]

排序算法作用在每一个tuple上，这里的t[0]是指每一个tuple的t[0]

#4 Created at ... [Delete] [Delete and Lock User]

我也理解不了，关于t[0]为什么不是第一个tuple,那如果我想取第一个tuple如何操作

#5 Created at ... [Delete] [Delete and Lock User]

因为L这个列表放到sorted里面排序，其实是把里面的元素都拆分开，然后执行key指定的函数，所以每1个tuple都作为参数放到函数里执行了，t[0]就是指tuple的第一个元素，by_name这个函数就是把每个tuple的名字单独弄出来进行排序，排序完再根据对应关系映射到原来的tuple

#6 Created at ... [Delete] [Delete and Lock User]

明白啦，谢谢小伙伴

#7 Created at ... [Delete] [Delete and Lock User]

sao

#8 Created at ... [Delete] [Delete and Lock User]

是否可以理解成：

#9 Created at ... [Delete] [Delete and Lock User]

def by_name(t): return t[0]

def by_score(t): return t[1]

#10 Created at ... [Delete] [Delete and Lock User]

说错了 t本身就是上边大tuple的其中一个小tuple，t[0]或者t[1]直接就是单个名字和分数，