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第一题

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beatMU

#1 Created at ... [Delete] [Delete and Lock User]

def normalize(name): name1=list(map(lambda x:x.title(),name)) return(name1) 为什么我的显示答案是[['A', 'D', 'A', 'M'], ['L', 'I', 'S', 'A'], ['B', 'A', 'R', 'T']]

大头爸爸爱臭臭

#2 Created at ... [Delete] [Delete and Lock User] 
# -*- coding: utf-8 -*-

def normalize(name):
    name = name.lower()
    name = name[0].upper() + name[1:]
    return name

L1 = ['adm','LISA','barT']
L2 = list(map(normalize,L1))
print(L2)

我就是八哥

#3 Created at ... [Delete] [Delete and Lock User]

我的理解是，map出来的一定也是一个序列，所以你这句

name1=list(map(lambda x:x.title(),name))

应该是相当于把每一个name里面的字符作为x.title的对象给格式化了

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