没看懂是啥意思， win7 环境下 拷贝了 廖大的文件丢在www目录下，运行报错...
Topic source按照如下修改即可解决
if __name__ == '__main__':
argv = sys.argv[1:]
if not argv:
print('Usage: ./pymonitor your-script.py')
exit(0)
if argv[0] != 'python': # 这里用python不要用python3除非你的系统也是用python3 XX.PY来启动python程序的
argv.insert(0, 'python')
command = argv
path = os.path.abspath('.')
start_watch(path, None)
我在win10下运行： 拷贝pymonitor.py到www目录下，再把文件中的python3改成python. if name == 'main': argv = sys.argv[1:] if not argv: print('Usage: ./pymonitor your-script.py') exit(0) if argv[0] != 'python': argv.insert(0, 'python') command = argv path = os.path.abspath('.') start_watch(path, None) 运行>python pymonitor.py app.py就ok了 ps：廖大这个python3 pymonitor.py wsgiapp.py里的wsgiapp.py指的是要启动的程序app.py吧，总之我是这样理解的
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一雷叔一
没看懂是啥意思， win7 环境下 拷贝了 廖大的文件丢在www目录下，运行报错...
[Monitor] Watching directory g:\Work File\awesome-python3-webapp\www... [Monitor] Start process python3 wsgiapp.py... Traceback (most recent call last): File "pymonitor.py", line 71, in <module> startwatch(path, None) File "pymonitor.py", line 54, in startwatch start_process() File "pymonitor.py", line 43, in start_process process = subprocess.Popen(command, stdin=sys.stdin, stdout=sys.stdout, stde rr=sys.stderr) File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35\lib\subpro cess.py", line 950, in __init restore_signals, start_new_session) File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35\lib\subpro cess.py", line 1220, in _execute_child startupinfo) FileNotFoundError: [WinError 2] 系统找不到指定的文件。