""" 请定义一个函数quadratic(a, b, c)，接收3个参数，返回一元二次方程： ax2 + bx + c = 0 的两个解 """ import math def quadratic(a,b,c): tmp = b * 2 - (4 a c) if tmp>0: x1 = (-b + math.sqrt(tmp)) / (2 a) x2 = (-b - math.sqrt(tmp)) / (2 a) print ("x1=%.2f,x2=%.2f"%(x1,x2)) elif tmp == 0: print ("x1=x2=%.2f"%(-b / (2 a))) else: print (r"don't have answer")
quadratic(2,3,1) quadratic(1,3,-4) quadratic(4,2,0.25) quadratic(4,2,3)
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叫我老陈行了吧
!/usr/bin/python3
""" 请定义一个函数quadratic(a, b, c)，接收3个参数，返回一元二次方程： ax2 + bx + c = 0 的两个解 """ import math def quadratic(a,b,c): tmp = b * 2 - (4 a c) if tmp>0: x1 = (-b + math.sqrt(tmp)) / (2 a) x2 = (-b - math.sqrt(tmp)) / (2 a) print ("x1=%.2f,x2=%.2f"%(x1,x2)) elif tmp == 0: print ("x1=x2=%.2f"%(-b / (2 a))) else: print (r"don't have answer")
quadratic(2,3,1) quadratic(1,3,-4) quadratic(4,2,0.25) quadratic(4,2,3)