#!/use/bin/env python3
# _*_ coding:utf-8 _*_
#规范名字
def normalize(name):
def a_A(n):
return A1[n]
def A_a(m):
return a1[m]
A1 = {'a':'A','b':'B','c':'C','d':'D','e':'E','f':'F','g':'G','h':'H','i':'I','j':'J','k':'K','l':'L','m':'M','n':'N','o':'O','p':'P','q':'Q','r':'R','s':'S','t':'T','u':'U','v':'V','w':'W','x':'X','y':'Y','z':'Z'}
a1 = {'A':'a','B':'b','C':'c','D':'d','E':'e','F':'f','G':'g','H':'h','I':'i','J':'j','K':'k','L':'l','M':'m','N':'n','O':'o','P':'p','Q':'q','R':'r','S':'s','T':'t','U':'u','V':'v','W':'w','X':'x','Y':'y','Z':'z'}
L_A,L_a = [],[]
for x in name[0]:
if x in A1:
L_A.append(a_A(x))
else:
L_A.append(x)
for y in name[1:]:
if y in a1:
L_a.append(A_a(y))
else:
L_a.append(y)
return L_A[0]+''.join(L_a)
L1 = ['adam', 'LISA', 'barT']
L2 = list(map(normalize, L1))
print(L2)
右上角的左下方
第一题(我是来搞笑的!!!):
第二题:
第三题: