lambda 函数改写
Topic source是酱紫才对吧~
def count():
def f(j):
return lambda :j*j
fs = []
for i in range(1,4):
fs.append(f(i))
return fs
- 1
是酱紫才对吧~
def count():
def f(j):
return lambda :j*j
fs = []
for i in range(1,4):
fs.append(f(i))
return fs
Mocking之书
def count(j): def f(j): return lambda : j*j fs = [] for i in range(1,4): fs.append(f(i)) return fs