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交作业啦

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杨森-ys

#1 Created at ... [Delete] [Delete and Lock User]

        double f = b*b-4*a*c;

        double f2 = Math.sqrt(f);

        double r1 = (-b+f2)/(2*a);

        double r2 = (-b-f2)/(2*a);

杨森-ys

#2 Created at ... [Delete] [Delete and Lock User]

        double f = b*b-4*a*c;   //定义变量f为浮点数double,用于接收求根公式的△。

        double f2 = Math.sqrt(f);  //△的平方根。用double

        double r1 = (-b+f2)/(2*a);   //根据求根公式分别列出两个根的运算

        double r2 = (-b-f2)/(2*a);

//添加了注释

Differ_锋

#3 Created at ... [Delete] [Delete and Lock User]

拆细写而已,其实可以整合一起,这样会很累


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