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用score进行排序

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用户5738893378

#1 Created at ... [Delete] [Delete and Lock User]

由于基本类型int并不能使用compareTo函数，因此在定义score时将int改为Integer：

class Person implements Comparable<Person>{    String name;    Integer score;    Person(String name, int score){        this.name = name;        this.score = score;    }    public int compareTo(Person other){        return this.score.compareTo(other.score);    }    public String toString(){        return this.name +","+this.score;    }}

廖雪峰

#2 Created at ... [Delete] [Delete and Lock User]

你这是学糊涂了，两个int比较：

this.score==other.score

Andylbc

#3 Created at ... [Delete] [Delete and Lock User]

return this.score - other.score;

_我是来微博看美女的

#4 Created at ... [Delete] [Delete and Lock User]

哈哈哈哈哈，我也是学糊涂了，一个劲儿的调用compaerTo方法去比较两个int类型的大小，结果编译报错，int类型是基本类型，直接比较就是了，不用调那个方法，廖老师点拨的很及时

求女票上微博

#5 Created at ... [Delete] [Delete and Lock User]

string 为什么 可以 直接调用 因为 本身重写了 compaerTo方法

当前 integer 也重写了 你定义integer 直接调用 compaerTo方法 我觉得 也没啥问题

Joker.fu_95

#6 Created at ... [Delete] [Delete and Lock User]

是没啥问题，只是多此一举

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