不明白这个表述

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#1 Created at ... [Delete] [Delete and Lock User]

job1.then(job2).then(job3).catch(handleError); 其中，job1、job2和job3都是Promise对象。不明白我觉得job1是Promise对象，job2,3应该是异步函数

蔚美似夏草

#2 Created at ... [Delete] [Delete and Lock User]

job2 job3 不是Promise对象,后面的then和cathch怎么执行

沙倫血夜

#3 Created at ... [Delete] [Delete and Lock User]

job2 job3也要有承諾(為Promise對象) 如果他們之間沒有共同承諾光只有job1單方面承諾也是沒有用的

男方我願意女方拒絕總不能強著來

匿名sina网友V

#4 Created at ... [Delete] [Delete and Lock User]

楼主的猜测是对的,文中表述不太严谨,廖大偶尔会手滑. 2楼3楼两位朋友太迷信,不是学习的正确态度.

var job2=function (r) {
    log('Done: ' + r);
};
var job3=function (reason) {
    log('Failed: ' + reason);
};

var job1 = new Promise(function (resolve, reject) {
    log('start new Promise...');
    var timeOut = Math.random() * 2;
    log('set timeout to: ' + timeOut + ' seconds.');
    setTimeout(function () {
        if (timeOut < 1) {
            log('call resolve()...');
            resolve('200 OK');
        }
        else {
            log('call reject()...');
            reject('timeout in ' + timeOut + ' seconds.');
        }
    }, timeOut * 1000);
}).then(job2).catch(job3);
console.log(job1 instanceof Promise);
console.log(typeof(job1));
//console.log(typeof(job1.then(job2)));
console.log(typeof(job2));
console.log(job2 instanceof Promise);
//console.log(typeof(job1.then(job3)));
console.log(typeof(job3));
console.log(job3 instanceof Promise);

用廖大自己的示例演示一下,job2,job3type是function,job1的type是object. job1.then(job2) 这个表达式才返回一个Promise,链式就得这样才玩得下去. 看见job1是Promise,就想当然地认为job2,job3也是promise,这是被廖大忽悠瘸了.