Discuss / JavaScript / 查找和过滤

查找和过滤

Topic source

terry_404

#1 Created at ... [Delete] [Delete and Lock User]

json = {}; var inputs = $('#test-form input[type!=radio],[checked],select').map(function(){ json[this.name] = this.value;});

json = JSON.stringify(json);

好像没什么美感


  • 1

Reply