新人求指教

董小姐cv

#1 Created at ... [Delete] [Delete and Lock User]

大佬为啥这个比较会返回false？

var arr = ['A', 'B', 'C', 'D', 'E', 'F', 'G']; var aCopy = arr.slice(); aCopy; // ['A', 'B', 'C', 'D', 'E', 'F', 'G'] aCopy === arr; // false

哪位大神解答一下不胜感激

芝草晟林

#2 Created at ... [Delete] [Delete and Lock User]

好像.slice()实现的是深拷贝

董小姐cv

#3 Created at ... [Delete] [Delete and Lock User]

也就是说这个复制完了之后数据类型不一样了是吗？

凭海听涛800

#4 Created at ... [Delete] [Delete and Lock User]

是浅拷贝吧，内存地址不同自然不同

饽饽灬

#5 Created at ... [Delete] [Delete and Lock User]

因为两数组无法进行直接比较。如需比较，需要两数组同时进行toString，之后比较才能返回true。

回忆淡忘97538

#6 Created at ... [Delete] [Delete and Lock User]

因为数组是Object对象，对象之间的比较实际上就是对比内存地址我帮你改了一下 var arr = ['A', 'B', 'C', 'D', 'E', 'F', 'G']; var aCopy = arr; console.log(arr === aCopy); 你在对比试一下就是ture了

console-log

#7 Created at ... [Delete] [Delete and Lock User]

内存地址不同，所以返回false，还是不明白的话，可以去了解下关于堆栈的东西

莫绯的M

#8 Created at ... [Delete] [Delete and Lock User]

slice浅拷贝返回了一个新的数组，开辟了一个新的内存空间，两个肯定不想等啊

我不是霍水

#9 Created at ... [Delete] [Delete and Lock User]

两个数组不能比较是不是相等，可以转化成字符串之后再比较可以考虑用toString()方法

hiochou

#10 Created at ... [Delete] [Delete and Lock User]

arr.sort(); console.log('欢迎' + arr[0] + ', ' + arr[1] + ', ' + arr[2] + '和' + arr[3] + '同学!'); console.log(欢迎${arr[0]}, ${arr[1]}, ${arr[2]}和${arr[3]}同学!);

新人求指教

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