DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9} def char2num(a): return DIGITS[a] def fn(x, y): return x * 10 + y i = 0 for x in s: if x == ".": break i = i + 1 return reduce(fn, map(char2num, s[:i])) + reduce(fn, map(char2num, s[i+1:])) / (10)**(len(s) - i - 1)
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沙耶子Ver3