def quadratic(a,b,c): if bb-4ac<0: print('该方程无解!') return else : x1=(-b+math.sqrt(bb-ac4))/(2a) x2=(-b-math.sqrt(bb-ac4))/(2*a) print('该方程的解为:') return x1,x2 quadratic(1,-2,1) 该方程的解为: (1.0, 1.0) quadratic(1,-1,-2013) 该方程的解为: (45.36925450684466, -44.36925450684466)
def quadratic(a,b,c): if bb-4ac<0: print('该方程无解!') return else : x1=(-b+math.sqrt(bb-ac4))/(2a) x2=(-b-math.sqrt(bb-ac4))/(2*a) print('该方程的解为:') return x1,x2
quadratic(1,-2,1) 该方程的解为: (1.0, 1.0) quadratic(1,-1,-2013) 该方程的解为: (45.36925450684466, -44.36925450684466)
求问为啥最后的quadratic(1,-1,-2013)解不一样
Sign in to make a reply
SaltedFishZzh
求问为啥最后的quadratic(1,-1,-2013)解不一样